Filter Absolute Numbers in array?

SystemAdmin - Wed Mar 11 09:20:15 EDT 2009
Look at the "reject" (and "accept") functions in DXL Help.

Doug.Zawacki - Wed Mar 11 14:37:11 EDT 2009
To answer your original question. Here is the code that should do as you expected. You needed to convert the absNo to a string and then set the filter at the end.

filtering on
int absNos[]={1,2,3,5} //normally this is populated via user input
absNosCount=sizeof(absNos)
Filter f=null
int i
for (i=0; i<absNosCount; i++)
{
int absNo=absNos[i]
if (f==null)
{ //seems to not work if not quoted, but can't quote int variable!
f=(attribute "Absolute Number" == absNo "")
}
else
{ //this syntax may not be legal:
f=f || (attribute "Absolute Number" == absNo "")
}
}
int iAccepted,iRejected
set(current,f,iAccepted,iRejected)

print "Filter =" stringOf(current,f) "\n"
print "Accepted: " iAccepted " -- Rejected: " iRejected "\n"

Doug.Zawacki - Wed Mar 11 14:37:11 EDT 2009
To answer your original question. Here is the code that should do as you expected. You needed to convert the absNo to a string and then set the filter at the end.

filtering on
int absNos[]={1,2,3,5} //normally this is populated via user input
absNosCount=sizeof(absNos)
Filter f=null
int i
for (i=0; i<absNosCount; i++)
{
int absNo=absNos[i]
if (f==null)
{ //seems to not work if not quoted, but can't quote int variable!
f=(attribute "Absolute Number" == absNo "")
}
else
{ //this syntax may not be legal:
f=f || (attribute "Absolute Number" == absNo "")
}
}
int iAccepted,iRejected
set(current,f,iAccepted,iRejected)

print "Filter =" stringOf(current,f) "\n"
print "Accepted: " iAccepted " -- Rejected: " iRejected "\n"

strathglass - Thu Mar 26 09:55:43 EDT 2009
Just learned one other important advantage of Doug's method:

If you just use accept and reject, you can filter as desired.
But this does not affect the filter functions current filter list:
so if you try to save your filtering done with accept and reject in a view it will not work:
the filtering is NOT saved (at least,not the filtering you did using accept/reject).

However with Doug's approach, the filter is a normal filter added to the filter function as the current filter:
this CAN be saved in a view!

Regards, strathglass

dpechacek - Wed Sep 23 17:18:10 EDT 2009

Hey guys. I'm trying to do this kind of filter. Getting a problem. Here's the code.
 

Object o;
      Filter f = null;
      Filter temp;
      Buffer objID = create();
      int absNum;
   
      for o in problemObjects do {
         objID = (string key(problemObjects));
         objID = objID[(contains(objID, '-')+1):];
         absNum = intOf(tempStringOf(objID));
         
         if(null(f)) {
            f = attribute "Absolute Number"  == absNum "";
         }
         else {
            f = f || attribute "Absolute Number"  == absNum "";
         } 
      }
      
      print stringOf(current, f) "\n";
      int accepted, rejected
      
      set(currentMod, f, accepted, rejected);
      filtering(on);
      refresh(currentMod);
      
      print accepted "\n"
      print rejected "\n"
      
      delete(objID);
      objID = null;

Now the code runs. Its just not applying the filter. I know its setting it because I can go turn on filtering manually and its the proper filter as well as the prints of accepted/rejected objects work. But its just not turning on filtering as it should be. Anyone see the problem?

AAI Services, Textron
dpechacek@aai.textron.com
David.Pechacek@gmail.com

llandale - Wed Sep 23 19:16:49 EDT 2009

Its working for me when I manually set your Skip problemObjects. My guess is that your 'currentMod' is no longer your current module, for whatever reason. If so, you are turning 'filtering(on)' on some other module, probably the one you opened to find your 'problemObjects'. Check it out: add

print "Current Module before filter = [" name(current Module) "]\n"

before your filtering(on) statement. You will perhaps need to "current = currentMod" before the filtering(on) statement.

I admit I'm surprised you don't need some form of 'filtering(off)' to get this going; but lets hope you do that when finding your problemObjects.

• Louie